I need a name to go with [name]Rosemarie[/name]. I want there to be the same number of letters as that in a name starting with [name]Cor[/name]-. I want their nicknames to be [name]Rose[/name] and [name]Cora[/name], but I can’t find a [name]Cor[/name]- name with 9 letters. So, think you can help?
The closest I can think of is [name]Cordelia[/name], which is 8 letters. I don’t know how you could make it any longer unless you used a really trendy spelling like Cordeelia or Cordeliah, neither of which I recommend at all.
I just thought of a name one of my friends loves, and she wondered if [name]Cora[/name] could work for it… it’s a bit of a stretch, but the name is [name]Concordia[/name]! Exactly 9 letters. I think [name]Cora[/name] as a nn could totally work, although I’m not sure how well [name]Rosemarie[/name] and [name]Concordia[/name] fit together…
That’s really all I can think of, unless you would consider using [name]Rosemary[/name] instead of [name]Rosemarie[/name] and then you could use [name]Cordelia[/name]…
Good luck!
[name]Corabelle[/name] or [name]Corabella[/name] are the only ones I can think of.
I like the suggestions of [name]Concordia[/name] and [name]Corabella[/name] I also like the suggestion of using [name]Rosemary[/name], in which case you could have [name]Cordelia[/name] or [name]Coraline[/name].
Other suggestions:
[name]Corallina[/name], Coralline
Corentine
Corinthia
[name]Corisande[/name], Corisanda
[name]Cornelija[/name]
Discordia
Coralinia
[name]Corallina[/name]
Coralline
[name]Corabelle[/name]
Coracynth- I think I mixed up [name]Cora[/name] and [name]Hyacinth[/name], but it maybe could work?
That’s tough! But [name]Concordia[/name] could work.
Corinthia
[name]Connemara[/name] (weird name I just discovered, dunno what I think of it but for me it combines some family names by sound, so that’s appealing - it’s a stretch to [name]Cora[/name], but it’s the first two and last two letters…)
[name]Constance[/name] with an R middle name?
[name]Coralynne[/name] - I think it’s pretty and goes well with [name]Rosemarie[/name].