LQ and QL brothers?

What would you name brothers with the initials LQ and QL?

For example:

[name_u]Lincoln[/name_u] [name_m]Quade[/name_m] and [name_u]Quincy[/name_u] [name_m]Lachlan[/name_m]

[name_m]Leyton[/name_m] [name_u]Quincy[/name_u] & [name_m]Quade[/name_m] [name_u]Laramie[/name_u]

Leonid Quill & Quince Leander

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[name_u]Lenny[/name_u] [name_u]Quill[/name_u] and [name_u]Quincy[/name_u] [name_u]Leland[/name_u]

[name_u]Laurence[/name_u] [name_u]Quill[/name_u] & [name_u]Quincy[/name_u] [name_u]Lark[/name_u]

laurie & quince

[name_m]Lucius[/name_m] [name_m]Quade[/name_m] & [name_u]Quentin[/name_u] [name_u]Lior[/name_u]

[name_m]Linus[/name_m] [name_m]Quigley[/name_m] and [name_u]Quincy[/name_u] [name_m]Leonard[/name_m]

[name_m]Luke[/name_m] [name_u]Quentin[/name_u] & [name_u]Quinn[/name_u] [name_u]Laurence[/name_u]

[name_m]Louis[/name_m] [name_m]Quaid[/name_m] & [name_u]Quincy[/name_u] [name_u]Lyle[/name_u]

[name_m]Ludo[/name_m] [name_u]Quentin[/name_u] & [name_u]Quill[/name_u] [name_u]Laurence[/name_u]

[name_m]Lysander[/name_m] [name_u]Quill[/name_u] & [name_m]Quaid[/name_m] [name_m]Leonardo[/name_m]

leon quimey & quest lennox

[name_u]Leo[/name_u] Quillian & [name_u]Quinn[/name_u] [name_m]Lysander[/name_m]

[name_m]Ludovic[/name_m] [name_u]Quinn[/name_u] and [name_u]Quentin[/name_u] [name_m]Leonardo[/name_m]

[name_m]Quinton[/name_m] [name_m]Louis[/name_m] and [name_u]Logan[/name_u] Quantray

[name_m]Link[/name_m] [name_u]Quarry[/name_u] & [name_u]Quill[/name_u] [name_u]Larkspur[/name_u]
[name_m]Link[/name_m] + [name_u]Quill[/name_u]

louis quincy + quentin loic

[name_u]Quincy[/name_u] [name_u]Laurence[/name_u] and [name_m]Louis[/name_m] [name_u]Quentin[/name_u]

[name_u]Leo[/name_u] [name_u]Quest[/name_u] and [name_u]Quinn[/name_u] [name_m]Lorcan[/name_m], probably? Maybe [name_u]Quinn[/name_u] [name_m]Linus[/name_m]. I like the look of [name_u]Quincy[/name_u] more than just [name_u]Quinn[/name_u] but I definitely prefer the idea of having a [name_u]Quinn[/name_u] to having a [name_u]Quincy[/name_u].